JEE Physics Practice Question

When vector $$\vec{A}=2 \hat{i}+3 \hat{j}+2 \hat{k}$$ is subtracted from vector $$\overrightarrow{\mathrm{B}}$$, it gives a vector equal to $$2 \hat{j}$$. Then the magnitude of vector $$\overrightarrow{\mathrm{B}}$$ will be :

1. A.3
2. B.$$\sqrt{33}$$
3. C.$$\sqrt6$$
4. D.$$\sqrt5$$