JEE Physics Practice Question
A drop of liquid of radius $\mathrm{R}=10^{-2} \mathrm{~m}$ having surface tension $\mathrm{S}=\frac{0.1}{4 \pi} \mathrm{Nm}^{-1}$ divides itself into $K$ identical drops. In this process the total change in the surface energy $\Delta U=10^{-3} \mathrm{~J}$. If $K=10^{\alpha}$ then what is the value of $\alpha$?
Want to know if you got it right?
Answer this and thousands more real JEE previous-year questions free, get graded instantly, and climb the global ranked leaderboard.
Practice JEE free →More JEE Physics questions
- A metal is heated in a furnace where a sensor is kept above the metal surface to read the …
- The isotope { }_{5}^{12} \mathrm{~B} having a mass 12.014 u undergoes \beta-decay to { }_{…
- A hydrogen atom in its ground state is irradiated by light of wavelength 970 A. Taking h c…
- Consider two solid spheres \mathrm{P} and \mathrm{Q} each of density 8 \mathrm{gm} \mathrm…
- Two inductors L_{1} (inductance 1 \mathrm{mH}, internal resistance 3 \Omega ) and L_{2} (i…
- An electron in a hydrogen atom undergoes a transition from an orbit with quantum number n_…
- A stationary source emits sound of frequency f_{0}=492 \mathrm{~Hz}. The sound is reflecte…
- { }^{131} \mathrm{I} is an isotope of Iodine that \beta decays to an isotope of Xenon with…