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Gaokao Physics Practice Question

用“中子活化”技术分析某样品的成分, 中子轰击样品中的 ${ }_{7}^{14} \mathrm{~N}$ 产生 ${ }_{6}^{14} \mathrm{C}$ 和另一种粒子 $\mathrm{X}$, 则 $\mathrm{X}$ 是

  1. A.质子
  2. B.$\alpha$ 粒子
  3. C.$\beta$ 粒子
  4. D.正电子

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