The number of real solutions of the equation $${x^2} - 3\left| x \right| + 2 = 0$$ is
JEE · Math · previous-year question
- A.3
- B.2
- C.4correct
- D.1
Answer
C. 4
Explanation
$${x^2} - 3\left| x \right| + 2 = 0$$ $$ \Rightarrow {\left| x \right|^2} - 3\left| x \right| + 2 = 0$$ $$\left( {\left| x \right| - 2} \right)\left( {\left| x \right| - 1} \right) = 0$$ $$\left| x \right| = 1,2$$ or $$x = \pm 1, \pm 2$$ $$\therefore$$ No. of solution $$=4$$
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