When vector $$\vec{A}=2 \hat{i}+3 \hat{j}+2 \hat{k}$$ is subtracted from vector $$\overrightarrow{\mathrm{B}}$$, it gives a vector equal to $$2 \hat{j}$$. Then the magnitude of vector $$\overrightarrow{\mathrm{B}}$$ will be :
JEE · Physics · previous-year question
- A.3
- B.$$\sqrt{33}$$
- C.$$\sqrt6$$
- D.$$\sqrt5$$
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