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The ordered pair (a, b), for which the system of linear equations 3x $$-$$ 2y + z = b 5x $$-$$ 8y + 9z = 3 2x + y + az = $$-$$1 has no solution, is :

JEE · Math · previous-year question

  1. A.$$\left( {3,{1 \over 3}} \right)$$
  2. B.$$\left( { - 3,{1 \over 3}} \right)$$
  3. C.$$\left( { - 3, - {1 \over 3}} \right)$$correct
  4. D.$$\left( {3, - {1 \over 3}} \right)$$

Answer

C. $$\left( { - 3, - {1 \over 3}} \right)$$

Explanation

$$\left| {\begin{matrix} 3 & { - 2} & 1 \\ 5 & { - 8} & 9 \\ 2 & 1 & a \\ \end{matrix} } \right| = 0 \Rightarrow - 14a - 42 = 0 \Rightarrow a = - 3$$ Now 3 (equation (1)) $$-$$ (equation (2)) $$-$$ 2 (equation (3)) is $$3(3x - 2y + z - b) - (5x - 8y + 9z - 3) - 2(2x + y + az + 1) = 0$$ $$ \Rightarrow - 3b + 3 - 2 = 0 \Rightarrow b = {1 \over 3}$$ So for no solution $$a = - 3$$ and $$b \ne {1 \over 3}$$

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