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If the pair of straight lines $${x^2} - 2pxy - {y^2} = 0$$ and $${x^2} - 2qxy - {y^2} = 0$$ be such that each pair bisects the angle between the other pair, then :

JEE · Math · previous-year question

  1. A.$$pq = -1$$correct
  2. B.$$p = q$$
  3. C.$$p = -q$$
  4. D.$$pq = 1$$.

Answer

A. $$pq = -1$$

Explanation

Equation of bisectors of second pair of straight lines is, $$q{x^2} + 2xy - q{y^2} = 0\,\,\,\,\,\,\,\,\,\,\,\,\,...\left( 1 \right)$$ It must be identical to the first pair $${x^2} - 2\,pxy - {y^2} = 0\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\left(... 2 \right)$$ from $$(1)$$ and $$(2)$$ $${q \over 1} = {2 \over { - 2p}} = {{ - q} \over { - 1}}$$ $$ \Rightarrow pq = - 1.$$

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