The sum of integers from 1 to 100 that are divisible by 2 or 5 is :
JEE · Math · previous-year question
- A.3000
- B.3050correct
- C.3600
- D.3250
Answer
B. 3050
Explanation
According to this question, any number between 1 to 100 should be divisible by 2 or 5 but not by 2$$ \times $$5 = 10. Possible numbers between 1 to 100 divisible by 2 are 2, 4, 6, .... , 100 This is an A.P where first term = 2, last term = 100 and total terms = 50. $$ \therefore $$ Sum of the numbers divisible by 2 = $${{50} \over 2}\left[ {2 + 100} \right]$$ = 25$$ \times $$102 = 2550 Possible numbers between 1 to 100 divisible by 5 are 5, 10, 15, .... , 100 $$ \therefore $$ Sum of the numbers divisible by 5 = $${{20} \over 2}\left[ {5 + 100} \right]$$ = 10$$ \times $$105 = 1050 And possible numbers between 1 to 100 divisible by 10 are 10, 20, 30, .... , 100 $$ \therefore $$ Sum of the numbers divisible by 10 = $${{10} \over 2}\left[ {10 + 100} \right]$$ = 5$$ \times $$110 = 550 $$ \therefore $$ Required sum = 2550 + 1050 - 550 = 3050
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