The relation $R=\{(x, y): x, y \in \mathbb{Z}$ and $x+y$ is even $\}$ is:
JEE · Math · previous-year question
- A.reflexive and transitive but not symmetric
- B.reflexive and symmetric but not transitive
- C.an equivalence relationcorrect
- D.symmetric and transitive but not reflexive
Answer
C. an equivalence relation
Explanation
$R=\{(x, y): x, y \in z$ and $x+y$ is even $\}$ reflexive $x+x=2 x$ even symmetric of $x+y$ is even, then $(y+x)$ is also even transitive of $\mathrm{x}+\mathrm{y}$ is even $\& \mathrm{y}+\mathrm{z}$ is even then $x+z$ is also even So, relation is an equivalence relation.
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