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If the roots of the equation $${x^2} - bx + c = 0$$ be two consecutive integers, then $${b^2} - 4c$$ equals

JEE · Math · previous-year question

  1. A.$$-2$$
  2. B.$$3$$
  3. C.$$2$$
  4. D.$$1$$correct

Answer

D. $$1$$

Explanation

Let $$\alpha ,\,\,\alpha + 1\,\,$$ be roots Then $$\alpha + \alpha + 1 = b = $$ sum of - roots $$\alpha \left( {\alpha + 1} \right) = c$$ $$=$$ product of roots $$\therefore$$ $${b^2} - 4c $$ $$ = {\left( {2\alpha + 1} \right)^2} - 4\alpha \left( {\alpha + 1} \right)$$ $$ = 1.$$

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