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Let N be the sum of the numbers appeared when two fair dice are rolled and let the probability that $$N-2,\sqrt{3N},N+2$$ are in geometric progression be $$\frac{k}{48}$$. Then the value of k is :

JEE · Math · previous-year question

  1. A.8
  2. B.16
  3. C.2
  4. D.4correct

Answer

D. 4

Explanation

$n-2, \sqrt{3 n}, n+2 \rightarrow$ G.P. $3 n=n^{2}-4$ $\Rightarrow n^{2}-3 n-4=0$ $\Rightarrow n=4,-1$ (rejected) $P(S=4)=\frac{3}{36}=\frac{1}{12}=\frac{4}{48}$ $\therefore k=4$

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