The value of $$\sum\limits_{r = 1}^{15} {{r^2}} \left( {{{{}^{15}{C_r}} \over {{}^{15}{C_{r - 1}}}}} \right)$$ is equal to :
JEE · Math · previous-year question
- A.560
- B.680
- C.1240
- D.1085
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