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A hyperbola whose transverse axis is along the major axis of the conic, $${{{x^2}} \over 3} + {{{y^2}} \over 4} = 4$$ and has vertices at the foci of this conic. If the eccentricity of the hyperbola is $${3 \over 2},$$ then which of the following points does NOT lie on it?

JEE · Math · previous-year question

  1. A.(0, 2)
  2. B.$$\left( {\sqrt 5 ,2\sqrt 2 } \right)$$
  3. C.$$\left( {\sqrt {10} ,2\sqrt 3 } \right)$$
  4. D.$$\left( {5,2\sqrt 3 } \right)$$correct

Answer

D. $$\left( {5,2\sqrt 3 } \right)$$

Explanation

$${{{x^2}} \over {12}} + {{{y^2}} \over {16}}$$ = 1 e = $$\sqrt {1 - {{12} \over {16}}} $$ = $${1 \over 2}$$ Foci (0, 2) & (0, $$-$$ 2) So, transverse axis of hyperbola = 2b = 4 $$ \Rightarrow $$ b = 2 & a2 = 12 (e2 $$-$$ 1) $$ \Rightarrow $$ a2 = 4$$\left( {{9 \over 4} - 1} \right)$$ $$ \Rightarrow $$ a2 = 5 $$ \therefore $$ It's equation is $${{{x^2}} \over 5} - {{{y^2}} \over 4}$$ = $$-$$ 1 The point (5, 2$$\sqrt 3 $$) does not satisfy the above equation.

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