Let $$\Delta ,\nabla \in \{ \wedge , \vee \} $$ be such that $$\mathrm{(p \to q)\Delta (p\nabla q)}$$ is a tautology. Then
JEE · Math · previous-year question
- A.$$\Delta = \vee ,\nabla = \vee $$
- B.$$\Delta = \vee ,\nabla = \wedge $$
- C.$$\Delta = \wedge ,\nabla = \wedge $$
- D.$$\Delta = \wedge ,\nabla = \vee $$
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