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Each of the angles $\beta$ and $\gamma$ that a given line makes with the positive $y$ - and $z$-axes, respectively, is half of the angle that this line makes with the positive $x$-axes. Then the sum of all possible values of the angle $\beta$ is

JEE · Math · previous-year question

  1. A.$\frac{\pi}{2}$
  2. B.$\pi$
  3. C.$\frac{3 \pi}{4}$correct
  4. D.$\frac{3 \pi}{2}$

Answer

C. $\frac{3 \pi}{4}$

Explanation

Given: Each of the angles $\beta$ and $\gamma$ is half of the angle that the line makes with the positive $x$-axis, i.e., $\beta = \gamma = \frac{\alpha}{2}$. The equation for the direction cosines of angles a line makes with the coordinate axes is given by: $ \cos^2 \alpha + \cos^2 \beta + \cos^2 \gamma = 1 $ Since $\beta = \gamma$, we substitute to get: $ \cos^2 \alpha + 2 \cos^2 \beta = 1 $ Substitute $\cos \beta = \cos \gamma$: $ \cos \alpha = 2 \cos^2 \beta - 1 $ Replacing back into the equation: $ (2 \cos^2 \beta - 1)^2 + 2 \cos^2 \beta = 1 $ Simplify: $ (2 \cos^2 \beta - 1)(2 \cos^2 \beta + 1) = 0 $ Solving for $\cos^2 \beta$, we have: $ 2 \cos^2 \beta - 1 = 0 \quad \text{or} \quad 2 \cos^2 \beta + 1 = 0 $ The latter gives no real solutions, thus: $ \cos^2 \beta = \frac{1}{2} $ Therefore, $\beta = \frac{\pi}{4}$ or $\beta = \frac{\pi}{2}$. Thus, the sum of all possible values of $\beta$ is: $ \frac{\pi}{4} + \frac{\pi}{2} = \frac{3\pi}{4} $

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