Let P be the plane, passing through the point (1,-1,-5) and perpendicular to the line joining the points (4,1,-3) and (2,4,3). Then the distance of P from the point (3,-2,2) is :

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Answer: A. 5 Equation of Plane : 2(x-1)-3(y+1)-6(z+5)=0 or 2 x-3 y-6 z=35 \Rightarrow Required distance = \frac{|2(3)-3(-2)-6(2)-35|}{\sqrt{4+9+36}} = 5

Let $P$ be the plane, passing through the point $(1,-1,-5)$ and perpendicular to the line joining the points $(4,1,-3)$ and $(2,4,3)$. Then the distance of $P$ from the point $(3,-2,2)$ is :

Answer

Explanation

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