Let P Q R be a triangle with R(-1,4,2). Suppose M(2,1,2) is the mid point of \mathrm{PQ}. The distance of the centroid of riangle \mathrm{PQR} from the point of intersection of the lines \frac{x-2}{0}=\frac{y}{2}=\frac{z+3}{-1} and \frac{x-1}{1}=\frac{y+3}{-3}=\frac{z+1}{1} is

Question

Let P Q R be a triangle with R(-1,4,2). Suppose M(2,1,2) is the mid point of \mathrm{PQ}. The distance of the centroid of 	riangle \mathrm{PQR} from the point of intersection of the lines \frac{x-2}{0}=\frac{y}{2}=\frac{z+3}{-1} and \frac{x-1}{1}=\frac{y+3}{-3}=\frac{z+1}{1} is

Accepted Answer

Answer: C. \sqrt{69} Centroid G divides MR in 1: 2 \mathrm{G}(1,2,2) Point of intersection A of given lines is (2,-6,0) \mathrm{AG}=\sqrt{69}

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