The equation of the chord, of the ellipse \frac{x^2}{25}+\frac{y^2}{16}=1, whose mid-point is (3,1) is :

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Answer: B. 48 x+25 y=169 \begin{aligned} &	ext { Equation of chord with given middle point }\ &\begin{aligned} & \mathrm{T}=\mathrm{S}_1 \ & \Rightarrow \frac{3 \mathrm{x}}{25}+\frac{\mathrm{y}}{16}-1=\frac{9}{25}+\frac{1}{16}-1 \ & 48 \mathrm{x}+25 \mathrm{y}=144+25 \ & 48 \mathrm{x}+25 \mathrm{y}=169 	ext { Ans. } \end{aligned} \end{aligned}

The equation of the chord, of the ellipse $\frac{x^2}{25}+\frac{y^2}{16}=1$, whose mid-point is $(3,1)$ is :

Answer

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