Let arg(z) represent the principal argument of the complex number z. Then, |z| = 3 and arg(z $$-$$ 1) $$-$$ arg(z + 1) = $${\pi \over 4}$$ intersect :
JEE · Math · previous-year question
- A.exactly at one point.
- B.exactly at two points.
- C.nowhere.
- D.at infinitely many points.
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