The number of real roots of the equation $x |x - 2| + 3|x - 3| + 1 = 0$ is :
JEE · Math · previous-year question
- A.4
- B.3
- C.2
- D.1correct
Answer
D. 1
Explanation
$$ \begin{aligned} & \text { (I) } x $$ & (II) 2 \leq x $$\mathrm{x}=\frac{-1+\sqrt{32}}{2}, \frac{-1-\sqrt{32}}{2}$$ $\quad \quad \times \qquad \qquad \times$ 1 real roots
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