If the domain of the function f(x)=\frac{[x]}{1+x^{2}}, where [x] is greatest integer \leq x, is [2,6), then its range is

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Answer: B. \left(\frac{5}{37}, \frac{2}{5}ight] f(x)=\frac{k}{1+x^{2}} is a decreasing function where k>0 \begin{gathered} 	herefore \quad x \in[2,3) \Rightarrow f(x)=\frac{2}{1+x^{2}} \in\left(\frac{2}{10}, \frac{2}{5}ight]=R_{1} \\ x \in[3,4) \Rightarrow f(x)=\frac{3}{1+x^{2}} \in\left(\frac{3}{17}, \frac{3}{10}ight]=R_{2} \\ x \in[4,5) \Rightarrow f(x)=\frac{4}{1+x^{2}} \in\left(\frac{4}{26}, \frac{4}{17}ight]=R_{3} \\ x \in[5,6) \Rightarrow f(x)=\frac{5}{1+x^{2}} \in\left(\frac{5}{37}, \frac{5}{26}ight]=R_{4} \\ 	ext { Range }=R_{1} \cup R_{2} \cup R_{3} \cup R_{4} \\ =\left(\frac{5}{37}, \frac{2}{5}ight] \end{gathered}

If the domain of the function $$f(x)=\frac{[x]}{1+x^{2}}$$, where $$[x]$$ is greatest integer $$\leq x$$, is $$[2,6)$$, then its range is

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