The number of common tangents to the circles $${x^2} + {y^2} - 4x - 6x - 12 = 0$$ and $${x^2} + {y^2} + 6x + 18y + 26 = 0,$$ is :
JEE · Math · previous-year question
- A.$$3$$
- B.$$4$$
- C.$$1$$
- D.$$2$$
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