Let N be the set of natural numbers and a relation R on N be defined by $$R = \{ (x,y) \in N \times N:{x^3} - 3{x^2}y - x{y^2} + 3{y^3} = 0\} $$. Then the relation R is :
JEE · Math · previous-year question
- A.symmetric but neither reflexive nor transitive
- B.reflexive but neither symmetric nor transitive
- C.reflexive and symmetric, but not transitive
- D.an equivalence relation
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