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Let x, y be positive real numbers and m, n positive integers. The maximum value of the expression $${{{x^m}{y^n}} \over {\left( {1 + {x^{2m}}} \right)\left( {1 + {y^{2n}}} \right)}}$$ is :

JEE · Math · previous-year question

  1. A.$${1 \over 2}$$
  2. B.$${1 \over 4}$$correct
  3. C.$${{m + n} \over {6mn}}$$
  4. D.1

Answer

B. $${1 \over 4}$$

Explanation

$${{{x^m}{y^n}} \over {\left( {1 + {x^{2m}}} \right)\left( {1 + {y^{2n}}} \right)}} = {1 \over {\left( {{x^m} + {1 \over {{x^m}}}} \right)\left( {{y^n} + {1 \over {{y^n}}}} \right)}} \le {1 \over 4}$$ using AM $$ \ge $$ GM

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