If in a G.P. of 64 terms, the sum of all the terms is 7 times the sum of the odd terms of the G.P, then the common ratio of the G.P. is equal to
JEE · Math · previous-year question
- A.7
- B.6correct
- C.5
- D.4
Answer
B. 6
Explanation
$$\begin{aligned} & a+a r+a r^2+a r^3+\ldots .+a r^{63} \\ & =7\left(a+a r^2+a r^4 \ldots .+a r^{62}\right) \\ & \Rightarrow \frac{a\left(1-r^{64}\right)}{1-r}=\frac{7 a\left(1-r^{64}\right)}{1-r^2} \\ & r=6 \end{aligned}$$
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