If $$\int {{{\tan x} \over {1 + \tan x + {{\tan }^2}x}}dx = x - {K \over {\sqrt A }}{{\tan }^{ - 1}}} $$ $$\left( {{{K\,\tan x + 1} \over {\sqrt A }}} \right) + C,(C\,\,$$ is a constant of integration) then the ordered pair (K, A) is equal to :
JEE · Math · previous-year question
- A.(2, 1)
- B.($$-$$2, 3)
- C.(2, 3)
- D.($$-$$2, 1)
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