JEE Math Practice Question
The area of the region in the first quadrant inside the circle $$x^2+y^2=8$$ and outside the parabola $$y^2=2 x$$ is equal to :
- A.$$\frac{\pi}{2}-\frac{1}{3}$$
- B.$$\pi-\frac{1}{3}$$
- C.$$\pi-\frac{2}{3}$$
- D.$$\frac{\pi}{2}-\frac{2}{3}$$
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