JEE Math Practice Question
The area enclosed by the curves $$y=\log _{e}\left(x+\mathrm{e}^{2}\right), x=\log _{e}\left(\frac{2}{y}\right)$$ and $$x=\log _{\mathrm{e}} 2$$, above the line $$y=1$$ is:
- A.$$2+\mathrm{e}-\log _{\mathrm{e}} 2$$
- B.$$1+e-\log _{e} 2$$
- C.$$e-\log _{e} 2$$
- D.$$1+\log _{e} 2$$
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