JEE Math Practice Question
The area bounded by the curve 4y2 = x2(4 $$-$$ x)(x $$-$$ 2) is equal to :
- A.$${\pi \over {16}}$$
- B.$${\pi \over {8}}$$
- C.$${3\pi \over {2}}$$
- D.$${3\pi \over {8}}$$
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