JEE Math Practice Question
The area (in sq. units) of the part of the circle x2 + y2 = 36, which is outside the parabola y2 = 9x, is :
- A.$$12\pi - 3\sqrt 3 $$
- B.$$24\pi + 3\sqrt 3 $$
- C.$$24\pi - 3\sqrt 3 $$
- D.$$12\pi + 3\sqrt 3 $$
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