JEE Math Practice Question
If the area (in sq. units) of the region {(x, y) : y2 $$ \le $$ 4x, x + y $$ \le $$ 1, x $$ \ge $$ 0, y $$ \ge $$ 0} is a $$\sqrt 2 $$ + b, then a – b is equal to :
- A.$${8 \over 3}$$
- B.$$ - {2 \over 3}$$
- C.6
- D.$${{10} \over 3}$$
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