JEE Math Practice Question
If the area (in sq. units) bounded by the parabola y2 = 4$$\lambda $$x and the line y = $$\lambda $$x, $$\lambda $$ > 0, is $${1 \over 9}$$ , then $$\lambda $$ is equal to :
- A.$$4\sqrt 3 $$
- B.2$$\sqrt 6 $$
- C.48
- D.24
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