JEE Math Practice Question
Let $$f: \rightarrow \mathbb{R} \rightarrow(0, \infty)$$ be strictly increasing function such that $$\lim \limits_{x \rightarrow \infty} \frac{f(7 x)}{f(x)}=1$$. Then, the value of $$\lim \limits_{x \rightarrow \infty}\left[\frac{f(5 x)}{f(x)}-1\right]$$ is equal to
- A.0
- B.4
- C.1
- D.7/5
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