JEE Math Practice Question
The slope of tangent at any point (x, y) on a curve $$y=y(x)$$ is $${{{x^2} + {y^2}} \over {2xy}},x > 0$$. If $$y(2) = 0$$, then a value of $$y(8)$$ is :
- A.$$ - 4\sqrt 2 $$
- B.$$2\sqrt 3 $$
- C.$$4\sqrt 3 $$
- D.$$ - 2\sqrt 3 $$
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