JEE Math Practice Question
$$\max \limits_{0 \leq x \leq \pi}\left\{x-2 \sin x \cos x+\frac{1}{3} \sin 3 x\right\}=$$
- A.$$\frac{5 \pi+2+3 \sqrt{3}}{6}$$
- B.0
- C.$$\frac{\pi+2-3 \sqrt{3}}{6}$$
- D.$$\pi$$
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