JEE Math Practice Question
Let $$x=2$$ be a local minima of the function $$f(x)=2x^4-18x^2+8x+12,x\in(-4,4)$$. If M is local maximum value of the function $$f$$ in ($$-4,4)$$, then M =
- A.$$18\sqrt6-\frac{33}{2}$$
- B.$$18\sqrt6-\frac{31}{2}$$
- C.$$12\sqrt6-\frac{33}{2}$$
- D.$$12\sqrt6-\frac{31}{2}$$
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