JEE Math Practice Question
The maximum value of the function f(x) = 3x3 – 18x2 + 27x – 40 on the set S = $$\left\{ {x\, \in R:{x^2} + 30 \le 11x} \right\}$$ is :
- A.$$-$$ 222
- B.$$-$$ 122
- C.$$122$$
- D.222
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