JEE Math Practice Question
Given that the slope of the tangent to a curve y = y(x) at any point (x, y) is $$2y \over x^2$$. If the curve passes through the centre of the circle x2 + y2 – 2x – 2y = 0, then its equation is :
- A.x loge|y| = 2(x – 1)
- B.x2 loge|y| = –2(x – 1)
- C.x loge|y| = x – 1
- D.x loge|y| = –2(x – 1)
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