JEE Math Practice Question
Let $$f\left( x \right) = {x^2} + {1 \over {{x^2}}}$$ and $$g\left( x \right) = x - {1 \over x}$$, $$x \in R - \left\{ { - 1,0,1} \right\}$$. If $$h\left( x \right) = {{f\left( x \right)} \over {g\left( x \right)}}$$, then the local minimum value of h(x) is
- A.$$2\sqrt 2 $$
- B.3
- C.-3
- D.$$-2\sqrt 2 $$
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