JEE Math Practice Question
The normal to the curve, $${x^2} + 2xy - 3{y^2} = 0$$, at $$(1,1)$$
- A.meets the curve again in the third quadrant.
- B.meets the curve again in the fourth quadrant.
- C.does not meet the curve again.
- D.meets the curve again in the second quadrant.
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