JEE Math Practice Question
Let $a_1, a_2, a_3, \ldots$ be in an A.P. such that $\sum\limits_{k=1}^{12} a_{2 k-1}=-\frac{72}{5} a_1, a_1 \neq 0$. If $\sum\limits_{k=1}^n a_k=0$, then $n$ is :
- A.18
- B.17
- C.11
- D.10
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