JEE Math Practice Question
If $$\frac{1}{\sqrt{1}+\sqrt{2}}+\frac{1}{\sqrt{2}+\sqrt{3}}+\ldots+\frac{1}{\sqrt{99}+\sqrt{100}}=m$$ and $$\frac{1}{1 \cdot 2}+\frac{1}{2 \cdot 3}+\ldots+\frac{1}{99 \cdot 100}=\mathrm{n}$$, then the point $$(\mathrm{m}, \mathrm{n})$$ lies on the line
- A.$$11(x-1)-100 y=0$$
- B.$$11 x-100 y=0$$
- C.$$11(x-1)-100(y-2)=0$$
- D.$$11(x-2)-100(y-1)=0$$
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