JEE Math Practice Question
Let $$s_{1}, s_{2}, s_{3}, \ldots, s_{10}$$ respectively be the sum to 12 terms of 10 A.P. s whose first terms are $$1,2,3, \ldots .10$$ and the common differences are $$1,3,5, \ldots \ldots, 19$$ respectively. Then $$\sum\limits_{i=1}^{10} s_{i}$$ is equal to :
- A.7360
- B.7220
- C.7260
- D.7380
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