JEE Math Practice Question

Let a$$_1$$, a$$_2$$, a$$_3$$, .... be a G.P. of increasing positive numbers. Let the sum of its 6th and 8th terms be 2 and the product of its 3rd and 5th terms be $$\frac{1}{9}$$. Then $$6(a_2+a_4)(a_4+a_6)$$ is equal to

1. A.2$$\sqrt2$$
2. B.2
3. C.3$$\sqrt3$$
4. D.3