JEE Math Practice Question
Let $a_1, a_2, a_3, \ldots$ be an A.P. If $a_7=3$, the product $a_1 a_4$ is minimum and the sum of its first $n$ terms is zero, then $n !-4 a_{n(n+2)}$ is equal to :
- A.24
- B.$\frac{381}{4}$
- C.9
- D.$\frac{33}{4}$
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