JEE Math Practice Question
Let a1, a2, a3, ..... be an A.P. If $${{{a_1} + {a_2} + .... + {a_{10}}} \over {{a_1} + {a_2} + .... + {a_p}}} = {{100} \over {{p^2}}}$$, p $$\ne$$ 10, then $${{{a_{11}}} \over {{a_{10}}}}$$ is equal to :
- A.$${{19} \over {21}}$$
- B.$${{100} \over {121}}$$
- C.$${{21} \over {19}}$$
- D.$${{121} \over {100}}$$
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