JEE Math Practice Question
The sum of the series $$\sum\limits_{n = 1}^\infty {{{{n^2} + 6n + 10} \over {(2n + 1)!}}} $$ is equal to :
- A.$${{41} \over 8}e + {{19} \over 8}{e^{ - 1}} - 10$$
- B.$${{41} \over 8}e - {{19} \over 8}{e^{ - 1}} - 10$$
- C.$${{41} \over 8}e + {{19} \over 8}{e^{ - 1}} + 10$$
- D.$$ - {{41} \over 8}e + {{19} \over 8}{e^{ - 1}} - 10$$
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