JEE Math Practice Question
The minimum value of $$f(x) = {a^{{a^x}}} + {a^{1 - {a^x}}}$$, where a, $$x \in R$$ and a > 0, is equal to :
- A.$$a + {1 \over a}$$
- B.2a
- C.a + 1
- D.$$2\sqrt a $$
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