JEE Math Practice Question
Let S be the sum of the first 9 terms of the series : {x + k$$a$$} + {x2 + (k + 2)$$a$$} + {x3 + (k + 4)$$a$$} + {x4 + (k + 6)$$a$$} + .... where a $$ \ne $$ 0 and x $$ \ne $$ 1. If S = $${{{x^{10}} - x + 45a\left( {x - 1} \right)} \over {x - 1}}$$, then k is equal to :
- A.-3
- B.1
- C.-5
- D.3
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