JEE Math Practice Question
The common difference of the A.P. b1, b2, … , bm is 2 more than the common difference of A.P. a1, a2, …, an. If a40 = –159, a100 = –399 and b100 = a70, then b1 is equal to :
- A.127
- B.81
- C.–127
- D.-81
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